(X-7)=(2x^2-5x+3)

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Solution for (X-7)=(2x^2-5x+3) equation: 



(X-7)=(2X^2-5X+3)

We move all terms to the left:

(X-7)-((2X^2-5X+3))=0

We get rid of parentheses

X-((2X^2-5X+3))-7=0



We calculate terms in parentheses: -((2X^2-5X+3)), so:

(2X^2-5X+3)

We get rid of parentheses

2X^2-5X+3

Back to the equation:

-(2X^2-5X+3)



We get rid of parentheses

-2X^2+X+5X-3-7=0

We add all the numbers together, and all the variables

-2X^2+6X-10=0

a = -2; b = 6; c = -10;
Δ = b2-4ac
Δ = 62-4·(-2)·(-10)
Δ = -44
Delta is less than zero, so there is no solution for the equation

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